带分数的二元一次方程组怎样解 (2x+y)/4-[来自5(x-2y)]/3=6 [3(2x+y)]/4-(x-y)/3=4
的有关信息介绍如下：![带分数的二元一次方程组怎样解 (2x+y)/4-[来自5(x-2y)]/3=6 [3(2x+y)]/4-(x-y)/3=4](/upload/images/2024/0910/a7217da9.jpg)
(2x+y)/4-[5(x-2y)]/3=6[3(2x+y)]陈支响迫旧环数磁抓云/4-(x-y)/3=4
(2x+y)/4-[5(x-2y)]/3=4
6[3(2x+y)]/4-(x-y)/3=4
俩个方程分别化简:
-14x+43y=48
52x+29y=24
俩式连列即可求解
带分数的二元一次方程组怎样解 (2x+y)/4-[来自5(x-2y)]/3=6 [3(2x+y)]/4-(x-y)/3=4
Simone
发布于 2025-07-02 15:35:20
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